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Home/ Questions/Q 9254959
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T11:36:11+00:00 2026-06-18T11:36:11+00:00

I currently have a method called getResult which returns const char* now I am

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I currently have a method called getResult which returns const char* now I am doing something like this

if(getResult=="Something")
{
  ...
}

However it seems this type of comparison doesn’t work. Isn’t “Something” also a const char pointer ? or in this case are the addresses being compared?

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  1. Editorial Team
    Editorial Team
    2026-06-18T11:36:12+00:00Added an answer on June 18, 2026 at 11:36 am

    If getResult is a method (member function) you need to call it to compare the result, so you probably want:

    if (something.getResult() == std::string("Something"))
      // ...
    

    If, on the other hand, getResult is really a pointer to char (or pointer to const char), you need to convert one of the things you’re comparing to string before the comparison):

    if (getResult == std::string("Something"))
    

    or:

    if (std::string(getResult) == "something))
    

    IMO, this should almost never be necessary — instead of starting with a pointer to [const] char, then converting, you should normally use std::string throughout.

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