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Home/ Questions/Q 6943415
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T13:09:10+00:00 2026-05-27T13:09:10+00:00

I currently have a selector that looks like this: $(span[row!=’2′][row!=’5′][row!=’1′]); Is there an easier

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I currently have a selector that looks like this:

$("span[row!='2'][row!='5'][row!='1']");

Is there an easier way to write this? I tried this but it didn’t work:

$("span[row!='1,2,5']");
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  1. Editorial Team
    Editorial Team
    2026-05-27T13:09:11+00:00Added an answer on May 27, 2026 at 1:09 pm

    No there is no way to combine not equal selectors in this manner. The result would be interpretted as the string '1,2,3' and not individual values. You’ll have to enumerate the cases.

    You could though write a function to make this easier to write. For example

    var makeNotEquals = function(name) {
      var clause = '';
      for (var i = 1; i < arguments.length; i++) {
        clause = clause + '[' + name + '!=\'' + arguments[i] + '\']';
      }
      return clause;
    }
    

    Usage

    var selector = 'span' + makeNotEquals('row', 2, 1, 5);
    $(selector) 
    
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