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Home/ Questions/Q 962259
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T01:28:41+00:00 2026-05-16T01:28:41+00:00

I currently have code for a subroutine to return a pointer to an array.

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I currently have code for a subroutine to return a pointer to an array. This array is a list of random numbers for a one dimensional monte-carlo integral. I am now trying to do a multi dimensional equivalent which requires 3 arrays of random numbers and instead of having a separate subroutine for each I’m trying to make one which returns a 3 by N + 1 array. Could somebody please help me with the coding for this. A mate mentioned I would need a double pointer but most web sources have been unhelpful thus far. Here is my single array code:

double* rdm_Y(void)
{
   double* Random_number_list_Y = calloc(N + 1, sizeof(double));
   int i;
   sleep(1);
   srand(time(NULL));
   for (i = 1; i <= N; i++) {
      Random_number_list_Y[i] = (float) rand() / (float) RAND_MAX;
   }
   return Random_number_list_Y;
}

Many Thanks!
Jack Medley

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T01:28:42+00:00Added an answer on May 16, 2026 at 1:28 am

    The general pattern for dynamically allocating a 2D array of type T (where T can be int, double, etc.) is

    #include <stdlib.h>
    
    T **alloc(size_t rows, size_t columns)  
    {
      T **arr = malloc(sizeof *arr, rows); // type of *arr is T *
      if (arr)
      {
        size_t i;
        for (i = 0; i < rows; i++)
        {    
          arr[i] = malloc(sizeof *arr[i], columns); // type of *arr[i] is T
          if (arr[i])
          {
            size_t j;
            for (j = 0; j < columns; j++)
            {
              arr[i][j] = initial_value_for_this_element;
            }
          }
        }
      }
      return arr;
    }
    
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