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Home/ Questions/Q 8267615
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T05:35:56+00:00 2026-06-08T05:35:56+00:00

I currently have code to roll over an image link as below: <a id=show

  • 0

I currently have code to roll over an image link as below:

<a id="show" href="#"><img src="images/show-me.png" border=0 onmouseover="this.src='images/show-me_over.png';" onmouseout="this.src='images/show-me.png'"></a>

on clicking this it shows a div

jQuery(document).ready(function(){
    jQuery("#show").toggle(
        function(){
            jQuery('#home-hidden-extra').animate({'height': '480px'} ,1000);},
        function(){
            jQuery('#home-hidden-extra').animate({'height': '0px'} ,1000);}
    );
});

What i would like to do but i cant find/figure out is to use show_me.png and show_me-over.png when the div is hidden and then hide_me.png and hide_me-over.png when the div is shown.

How is the simplest way to achive this?

Thanks again!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T05:35:58+00:00Added an answer on June 8, 2026 at 5:35 am

    You should be putting static hover styles to CSS. Define

    .linkShow {
        background-image: url("images/show_me.png");
    }
    
    .linkShow:hover {
        background-image: url("images/show_me_hover.png"); 
    }
    
    .linkHide {
        background-image: url("images/hide_me.png");
    }
    
    .linkHide:hover {
        background-image: url("images/hide_me_hover.png"); 
    }
    

    Then add these classes to the link with jquery.

    $("#show").removeClass().addClass("linkShow");
    
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