Question

I defined a EditText in XML with attribute android:inputType=”numberSigned”, so, when I try to get it in Java Code like:

int type = mEditText.getInputType();
switch(type){
case InputType.TYPE_NUMBER_FLAG_SIGNED:
//do when I get EditText defined with 'numberSinged'
//do something
break;
}

But, It doesn’t work for me. So I try to check Android source code, TYPE_NUMBER_FLAG_SIGNED=4096. When I try to print println(mEditText.getInputType()),it turns to be 4098. And I can’t find any variable equals 4098.
Can anybody tell me the reason?

I’m not good at English, may you can understand me! Thanks!

Answer 1

there can be multiple flags assigned to inputType. To find out if a flag is set or not, use the bitwise AND (&) operator:

int type = mEditText.getInputType();
if((type & InputType.TYPE_NUMBER_FLAG_SIGNED) > 0)
{
    // your stuff here
}

I guess, the usage of switch case is not possible here.