Question

I didn’t make the image into binary form, but want to get that image data from database now.
So can you give so idea about that.
I have done like below to insert image:

FileDialog dialog = new OpenFileDialog();
dialog.InitialDirectory = @":D\";
dialog.Filter = "(*.jpg;*.gif;*.jpeg;*.bmp)| *.jpg; *.gif; *.jpeg; *.bmp";
if (dialog.ShowDialog() == DialogResult.OK)
{
    imagename = dialog.FileName;
    pictureBox1.Image = Image.FromFile(imagename);
}
dialog = null;

Then it also store in database but now I have to retrive the image in next form how can I do?

Answer 1

    int O_id =Convert.ToInt32(textBox2.Text);

            SqlConnection cn = new SqlConnection(strCn);
            SqlCommand cmd = new SqlCommand("INSERT INTO BLOBTest (BLOBData, O_id) VALUES (@BLOBData,'"+O_id+"')", cn);
            String strBLOBFilePath = textBox1.Text;//Modify this path as needed.


            //Read jpg into file stream, and from there into Byte array.
            FileStream fsBLOBFile = new FileStream(strBLOBFilePath, FileMode.Open, FileAccess.Read);
            Byte[] bytBLOBData = new Byte[fsBLOBFile.Length];
            fsBLOBFile.Read(bytBLOBData, 0, bytBLOBData.Length);
            fsBLOBFile.Close();

            //Create parameter for insert command and add to SqlCommand object.
            SqlParameter prm = new SqlParameter("@BLOBData", SqlDbType.VarBinary, bytBLOBData.Length, ParameterDirection.Input, false,
                        0, 0, null, DataRowVersion.Current, bytBLOBData);
            cmd.Parameters.Add(prm);

            //Open connection, execute query, and close connection.
            cn.Open();
            cmd.ExecuteNonQuery();
            MessageBox.Show("Picture has been uploaded");
            cn.Close();