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Editorial Team
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Asked: 2026-06-07T05:45:53+00:00

I don’t know if it is possible, I am using php with zend-framwork and

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I don’t know if it is possible, I am using php with zend-framwork and i want to show an editor for the user in a pop-up window.

I want to submit this form back to the original window and close the window.

1)The problem is i cant view the form using $this->view->form = $form and echo it in the view of that action ? and i am using this code to popup the new window. i tried to solve this problem by echo the form from the controller,it worked but i couldn’t submit anywhere.

<a href="#" onClick="MyWindow=window.open('<?php echo $this->url(array('module' => 'default', 'controller' => 'index', 'action' => 'editor'));         ?>','MyWindow','toolbar=no,location=no,directories=no,status=no, menubar=no,scrollbars=no,resizable=no,width=600,height=300'); return false;">Click Here</a>

2)how to return the pop-up window to the original window or even is that possible?

If my question missing something please ask.

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1 Answer

  1. Editorial Team

    You can use window.opener property in script of opened popup window.
    like this 

    window.opener.TheMethodOfParentWindow(ValueOfTheEditor);
window.close();

    I have written a detail post here on this topic if you want to check:
    http://rupeshpatel.wordpress.com/2012/05/15/how-to-call-javascript-function-of-parent-window-from-new-pop-up-window/

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