Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6878747
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T04:45:42+00:00 2026-05-27T04:45:42+00:00

I don’t know if this is the best way to form this linq query,

  • 0

I don’t know if this is the best way to form this linq query, but I’m just getting started so any advice is appreciated.

The following query I think says “Reports that have any items where the items have any attibutes where the sizing attribute’s waiste size property is 32.” return the Report’s Location Key, ID and Name. (Location is a foreign key from Report.)

        var rpts = from x in ctx.Reports
                   where x.ReportItems.Any(y =>
                       y.ItemAttributes.Any(z =>
                           z.Sizing.WaistSize == 32))
                   select new { x.Key, x.Location.ID, x.Location.Name };

This produces the desired results but the SQL doesn’t seem right to me. Notice the LEFT OUTER JOIN to get the Location Name, when it could have just gotten it from the first INNER JOIN to the same table…

SELECT [Extent1].[ReportKey] AS [ReportKey], 
       [Extent2].[LocationID] AS [LocationID], 
       [Extent3].[LocationName] AS [LocationName]
FROM   [Info].[Report] AS [Extent1]
INNER JOIN [Info].[Location] AS [Extent2] 
ON [Extent1].[LocationKey] = [Extent2].[LocationKey]
LEFT OUTER JOIN [Info].[Location] AS [Extent3] 
ON [Extent1].[LocationKey] = [Extent3].[LocationKey]
WHERE  EXISTS 
(SELECT 1 AS [C1]
FROM ( SELECT [Extent4].[ReportItemKey] AS [ReportItemKey]
       FROM [Info].[ReportItems] AS [Extent4]
       WHERE [Extent1].[ReportKey] = [Extent4].[ReportKey]
     )  AS [Project1]
WHERE EXISTS (SELECT 1 AS [C1]
         FROM  [Info].[ItemAttributes] AS [Extent5]
         INNER JOIN [Info].[Attributes] AS [Extent6] 
                   ON [Extent5].[AttributeKey] = [Extent6].[AttributeKey]
         WHERE ([Project1].[ReportItemKey] = [Extent5].[ReportItemKey]) 
                   AND ([Extent6].[WaistSize] = @p__linq__0)
             )
 )

Thanks for the time.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-27T04:45:42+00:00Added an answer on May 27, 2026 at 4:45 am

    If you want an inner join you will have to write something like this

    from x in ctx.Reports
    join y in ctx.Locations
    on x.LocationKey equals y.ID
    where x.ReportItems.Any(y =>
           y.ItemAttributes.Any(z =>
               z.Sizing.WaistSize == 32))
       select new { x.Key, y.ID, y.Name };
    

    What you wrote by saying x.Location.ID in the select statement is to navigate to the entity Location, it doesn’t check to see whether you have handled the situation where x.Location is null, it just assumes that you know that if a report doesn’t have a location your code will break.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Don't know how to google for such, but is there a way to query
Don't know why this is happening, but after submitting a form via JS (using
(Don't know if this is strictly on-topic, but I don't see any better Stack
I don't know why, but this code worked for me a month ago... maybe
Don't ask why, but is there any way to suppress a failed linking error?
Don't know if this is the right place to ask this, but I will
Don't know if this is an eclipse specific problem but whenever I declare a
Don't know if I'm over-thinking this or not.. but I'm trying to be able
Don't know whether I'm having a "thick day" - but I just wondered what
Don't know why but I can't find a solution to this. I have 3

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.