I don’t really know much PHP. But anyways I am not able to upload

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Asked: June 9, 20262026-06-09T16:23:10+00:00 2026-06-09T16:23:10+00:00

I don’t really know much PHP. But anyways I am not able to upload

0

I don’t really know much PHP. But anyways I am not able to upload a .csv file using the following php. The file is less the 5MB. What’s going on? There are a total of 79,500 rows of records with just four columns and simple value like such:

27589   16990   161.7000095 0.838494
27589   17067   161.7000095 0.838494
27820   17144   315.7000095 0.859458
27820   17221   315.7000095 0.859458
27820   17606   315.7000095 0.866033
27820   17683   315.7000095 0.866033

I dissected the file and uploaded up to 60,000 rows of data and bombed out, which is 1.93MB. Anything beyond that just doesn’t work. The error code is ” — CSV file to load: failure to upload the file >>> Error code: 1
” error code 1.

Also how do I print a complete PHP error message instead of just the value “1” which I’m not sure what it corresponds to? ie… output print like this “UPLOAD_ERR_INI_SIZE: 1”?

<?php
// using upload at click from http://code.google.com/p/upload-at-click/
// FileData is the name for the input file

$file_result = "";
$file = $_FILES['Filedata'];

$allowedExtensions = array("csv", "txt");
$arrayVar = explode(".", $file["name"]);
$extension = end($arrayVar);

//commented out for “Only variables should be passed by reference” error
//$extension = end(explode(".", $file["name"]));


function isAllowedExtension($fileName) {
    global $allowedExtensions;
    return in_array(end(explode(".", $fileName)), $allowedExtensions);
}

if($file["error"] > 0){
    echo "failure to upload the file >>> ". "Error code: ".$file["error"]."<br>";
}else{
    //echo " >>> CURRENT DIR: ".getcwd() . "\n";
    $workDir = getcwd();

    $dir = substr($workDir, 0, -10);
    $path = $file["name"];
    $newFileLoc = $dir.$path;

    $file_result.=
    "<br>     Upload: " . $file["name"] . "<br>" .
    "     Type: " . $file["type"] . "<br>" .
    "     Size: " . $file["size"] . "<br>" .
    "     file uploaded to: ".$newFileLoc."<br>";

    // txt - text/plain
    // rtf - application/msword
    // dat/obj - application/octet-stream
    // csv - application/vnd.ms-excel
    // maximum 200 MB file - 200,000,000 k

    if (    ($file["type"] == "application/vnd.ms-excel" || $file["type"] == "text/plain")
            && isAllowedExtension($file["name"])
            && ($file["size"] < 200000000)
        )
        {   
            move_uploaded_file($file["tmp_name"], $newFileLoc);
            //echo $file_result.=" >>> File uploaded successfull!!";
            echo "|".$path;//"filePath : " . $newFileLoc;

        }else{
            echo " >>> NOT a file valid: ". isAllowedExtension($file["name"]);
        }       
}

?>

This is the line that was added as suggested by another user to catch the error correctly. Please let me know if that’s right sorry i don’t know much PHP at all. Anyways, the error printed is just “– CSV file to load: failure to upload the file >>> Error code: 1
“

<?php
// using upload at click from http://code.google.com/p/upload-at-click/
// FileData is the name for the input file

ini_set('display_errors', 1); error_reporting(E_ALL);

$file_result = "";
$file = $_FILES['Filedata'];

$allowedExtensions = array("csv", "txt");
$arrayVar = explode(".", $file["name"]);
$extension = end($arrayVar);