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Home/ Questions/Q 6738011
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T11:19:00+00:00 2026-05-26T11:19:00+00:00

I don’t understand why the following code doesn’t work. (jQuery 1.6.4) HTML: <div class=test></div>

  • 0

I don’t understand why the following code doesn’t work. (jQuery 1.6.4)

HTML:

<div class="test"></div>
<div class="test"></div>
<div class="test"></div>
<div class="test"></div>
<div class="test"></div>
<div class="test me"></div>
<div class="test me"></div>
<div class="test me"></div>

JS:

var rows = $([]);

console.debug('Divs we want: ', $('div:not(.me)').length);

console.debug('Rows before: ', rows.length);

$('div:not(.me)').each(function() {
    if (1==1) { // some conditional
        console.debug($(this));
        rows.add($(this));
    }
});

console.debug('Rows after: ', rows.length);
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  1. Editorial Team
    Editorial Team
    2026-05-26T11:19:00+00:00Added an answer on May 26, 2026 at 11:19 am

    add() builds and returns a new jQuery object from the contents of the one it’s called on and the argument you supply. It does not update the object it’s called on.

    You probably want to write:

    rows = rows.add(this);
    

    As an aside, since jQuery 1.4 the canonical way to construct an empty jQuery object is to call $() without arguments:

    var rows = $();
    
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