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Home/ Questions/Q 8079319
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T16:03:58+00:00 2026-06-05T16:03:58+00:00

I don’t want to do it the formal way by using a for loop

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I don’t want to do it the formal way by using a for loop that goes over all the elements of the string a “particular no. of times”(length of string) .

Is there any character that is always at the end of every string in Java just like it it in c ?

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  1. Editorial Team
    Editorial Team
    2026-06-05T16:04:00+00:00Added an answer on June 5, 2026 at 4:04 pm

    You have two basic options:

    String myString = "ABCD";
    for (char c : myString.toCharArray())
    {
      System.out.println("Characer is " + c);
    }
    
    for (int i = 0; i < myString.length(); i++)
    {
      System.out.println("Character is " + myString.charAt(i));
    }
    

    The first loops through a character array, the second loops using a normal indexed loop.

    Java does however, support characters like ‘\n’ (new line). If you want to check for the presence of this character, you can use the indexOf(‘\n’) method that will return the position of the character, or -1 if it could not be found. Be warned that ‘\n’ characters are not required to be able to end a string, so you can’t rely on that alone.

    Strings in Java do NOT have a NULL terminator as in C, so you need to use the length() method to find out how long a string is.

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