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Home/ Questions/Q 1898688
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T06:47:49+00:00 2026-05-17T06:47:49+00:00

i don’t what this process is called, but i’ve seen that it’s possible. what

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i don’t what this process is called, but i’ve seen that it’s possible.
what is this process called?

basically, i have a method that has a loop, and in every iteration has a delay second.

function myLoop(float delay)
{
    for(int x=0; x<100; x++)
    {
        Print("Loop number: " + x);
        TimeDelay(delay);
    }
}

i’d like to run the second instance without waiting until the first instance is finished.

function main()
{
     myLoop(2);
     myLoop(2);
}

so once the first myLoop started, i’d like the second myLoop to start immediately, they would be both running at the same time, my question is, what do you call this process?
is this process possible?(in java for example).

Thank you very much! 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T06:47:50+00:00Added an answer on May 17, 2026 at 6:47 am

    Java implementation of your program will be similar to this.

        class MyThread implements Runnable{
           Thread t;
           int delay;
           MyThread (int delay) {
              t = new Thread(this,"My thread");
              this.delay = delay;
              t.start();
           }
           public void run() {
              for(int x=0; x<100; x++)
              {
               Print("Loop number: " + x);
               TimeDelay(delay);
              }
          }
        }
        class Demo {
           public static void main (String args[]){
             Thread t1 = new MyThread(2);
             Thread t2 = new MyThread(2);
             t1.join();
             t2.join();    
           }
        }
    
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