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Home/ Questions/Q 9001129
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T00:23:44+00:00 2026-06-16T00:23:44+00:00

i don’t why i’m getting this exception ! my method is very simple it

  • 0

i don’t why i’m getting this exception !
my method is very simple it will loop to fill my parallel arrays
here is my method

public void fillPhoneBook(){
    Scanner in = new Scanner(System.in);
    for(int i=0;i<this.names.length;i++){
        System.out.println("Enter Name:");
        this.names[i] =in.next();
        System.out.println("Enter Phone Number:");
        this.telephones[i]=in.next();//here start rising exception 
    }
    in.close();

i get this exception after the second input !`

— UPDATE —

sorry the problem was with initializing the telephones array

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T00:23:45+00:00Added an answer on June 16, 2026 at 12:23 am

    I have created the same scenario as you explained but the strange thing is that I am not getting any such exception. Please have a look at the code below

    public class TestScanner {
        String names[] = new String[10];
        String telephones[] = new String[10];
    
        public static void main(String a[]) {
    
            TestScanner p = new TestScanner();
    
            Scanner in = new Scanner(System.in);
            for (int i = 0; i < p.names.length; i++) {
                System.out.println("Enter Name:");
                p.names[i] = in.next();
                System.out.println("Enter Phone Number:");
                p.telephones[i] = in.next();// here start rising exception
            }
            in.close();
    
        }
    }
    

    Output

    Enter Name:
    test1
    Enter Phone Number:
    123456
    Enter Name:
    test2
    Enter Phone Number:
    456789
    Enter Name:
    
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