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Home/ Questions/Q 9031471
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T07:44:26+00:00 2026-06-16T07:44:26+00:00

I found code here that looked something like this: auto f(T& t, size_t n)

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I found code here that looked something like this:

auto f(T& t, size_t n) -> decltype(t.reserve(n), void()) { .. }

In all the documentation I read I was told that decltype is signed as:

decltype( entity )

or

decltype( expression )

And there is no second argument anywhere. At least that’s what’s pointed to on cppreference. Is this a second argument to decltype? And if so, what does it do?

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  1. Editorial Team
    Editorial Team
    2026-06-16T07:44:27+00:00Added an answer on June 16, 2026 at 7:44 am

    Since it is an expression that comma is simply the comma operator (meaning the type is the type of the rhs side: void), not another argument.

    That code is using SFINAE – it’s enabled if t.reserve(n) exists but it wants to keep the return type as void.

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