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Home/ Questions/Q 8120515
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T05:10:52+00:00 2026-06-06T05:10:52+00:00

I found this line of code in some code I’m analyzing: Mintau = (double*)

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I found this line of code in some code I’m analyzing:

Mintau = (double*) malloc(FadeAll.num_paths*sizeof(double));

I also found a question on here (that was a duplicate of other questions it appears) that explains different syntax of pointers including:

int *ptr;  
int * ptr;  
int* ptr; 

I should explain that I fully understand that all three of the above are saying the same thing. The last one is the one that most closely resembles my line of code. What I was wondering is why double has to be in parenthesis in this case? I apologize if this is a duplicate question but I couldn’t find any regarding this.

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  1. Editorial Team
    Editorial Team
    2026-06-06T05:10:53+00:00Added an answer on June 6, 2026 at 5:10 am

    There are no difference between this three declarations:

    int *ptr;  
    int * ptr;  
    int* ptr; 
    

    (double*) has to be in parenthesis because it is a Cast.

    Read a little about casting in this link

    Hope it helps.

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