Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8861885
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 14, 20262026-06-14T15:35:36+00:00 2026-06-14T15:35:36+00:00

I got a left_column with a #form, when I sumbmit it should load the

  • 0

I got a left_column with a #form, when I sumbmit it should load the results on #content_div without refreshing the page.

Im using this:

<script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script>
<script type="text/javascript" src="http://ajax.microsoft.com/ajax/jquery.validate/1.7/jquery.validate.min.js"></script>
<script type="text/javascript">
$(function() {
    $('#dateform').submit(function(evt) {
        evt.preventDefault();
        $.ajax({
            url: "charts/client.php",
            type: 'POST',
            data: $(this).serialize(),
            success: function(result) {
                $('#content_div').html(result);
            }
        });
    });
});
</script>
<div id="content_div">

Nothing seems to appear.
And firebug reports this:

ReferenceError: google is not defined

This charts/client.php is using google api, and yes i’ve declared it like this:

<script language="javascript" type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.0/jquery.min.js"></script>
<script type="text/javascript" src="https://www.google.com/jsapi"></script>

What am I doing wrong?
Thanks

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-14T15:35:38+00:00Added an answer on June 14, 2026 at 3:35 pm

    use ajax form

    <script>
        // wait for the DOM to be loaded
        $(document).ready(function() 
        {
            // bind 'myForm' and provide a simple callback function
           $("#tempForm").ajaxForm({
           url:'../calling action or servlet',
           type:'post',
           beforeSend:function()
           {
             alert("perform action before making the ajax call like showing soinner image");
           },
           success:function(e){
            alert("data is"+e);
                alert("now do whatever you want with the data");
           }
           });
        });
    </script>
    

    you can find the plugin here

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Got this error message while trying to load view: The model item passed into
I am using opencart, just got this error when trying to view customers in
I've got a few divs (multi-column page) with display: inline-block set. Shouldn't this prevent
So I've got a simple bio type page with a series of images on
Was hoping for some fresh eyes on this. I've got a page which will
I've got the following type of SQL: UPDATE photo AS f LEFT JOIN car
I got a series of divs like this: <div class=message style=padding-left: 0px;>...</div> <div class=message
Got a question for some jQuery wizard who might stumble upon this. When I
I am using Visual Studio 2008 and VB.NET. I've got a listview control on
I've got a sub-select in a query that looks something like this: left outer

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.