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Home/ Questions/Q 8608031
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T03:30:53+00:00 2026-06-12T03:30:53+00:00

I have 2 tables – events and attendees. I am trying using php to

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I have 2 tables – events and attendees.

I am trying using php to when clicking on the attendee’s list via the events.id and to display the attendees listed in the attendees table linked by id.

fields envolved are events.id and attendees.id and to display the attendees for that event.

This is what I have at the moment.

SELECT events.*, attendees.* 
FROM attendees ON event.id = attendees.id 
WHERE event.id = attendees.id
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T03:30:54+00:00Added an answer on June 12, 2026 at 3:30 am

    Your joining syntax is an incorrect mix of implicit and explicit JOIN syntaxes, missing the JOIN keyword, and instead duplicating the join condition in the WHERE clause.

    SELECT
      events.*, 
      attendees.* 
    FROM
      attendees 
      JOIN events ON event.id = attendees.id
    WHERE
      event.id = <event to find attendees for>
    

    Note that it is not advisable to use events.*, attendees.* in PHP, since you will have duplicate column names that become inaccessible to PHP. Instead, be explicit:

    SELECT
      /* Be explicit about the columns you select in a JOIN query */
      events.id AS event_id,
      events.name AS event_name,
      events.someothercol,
      attendees.id AS attendee_id,
      attendees.name AS attendee_name
    FROM
      attendees 
      JOIN events ON event.id = attendees.id
    WHERE
      event.id = <event to find attendees for>
    

    If you still want to get the event details even if it has no attendees, use a LEFT JOIN instead:

    SELECT
      /* Be explicit about the columns you select in a JOIN query */
      events.id AS event_id,
      events.name AS event_name,
      events.someothercol,
      attendees.id AS attendee_id,
      attendees.name AS attendee_name
    FROM
      events
      /* LEFT JOIN will return event details even when there are no attendees */
      LEFT JOIN attendees ON event.id = attendees.id
    WHERE
      event.id = <event to find attendees for>
    
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