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Home/ Questions/Q 7779291
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T18:36:47+00:00 2026-06-01T18:36:47+00:00

I have a basic structure like this typedef struct struck { char* id; char*

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I have a basic structure like this

typedef struct struck {
    char* id;
    char* mat;
    int value;
    char* place;
} *Truck;

And afunction like this which creates a new “instance” of that struct:

Truck CTruck(char* id, char* mat, int value, char* place) {
    Truck nT = (Truck) malloc(sizeof (Truck));
    nT->value = value;
    strcpy(nT->id, id);
    strcpy(nT->mat, mat);
    strcpy(nT->place, place);
    return nT;
}

I’m getting an error in the first strcpy. It compiles without problem.

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  1. Editorial Team
    Editorial Team
    2026-06-01T18:36:49+00:00Added an answer on June 1, 2026 at 6:36 pm

    Your typedef defines Truck as a struct struck *, i.e. a pointer. So it’s size will be 4 or 8 depending on the architecture and not the size of the struct

    Use sizeof(*Truck) to get the actual size of the struct.

    You also need to allocate memory for the characters. The easiest way would be using strdup().

    Truck CTruck(const char* id, const char* mat, int value, const char* place) {
        Truck nT = malloc(sizeof (*Truck));
        nT->value = value;
        nT->id = strdup(id);
        nT->mat = strdup(mat);
        nT->place = strdup(place);
        return nT;
    }
    

    However, I would suggest changing your typedef so it’s an alias for the struct, not for a pointer to it:

    typedef struct {
        char* id;
        char* mat;
        int value;
        char* place;
    } Truck;
    

    In your function you then use this:

    Truck *nT = malloc(sizeof(Truck));
    
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