Question

I have a C++ template function which prints numbers.

It works fine for everything, except when I’m working with data of type char.

I’d like char to be printed as int, but if I cast this explicitly in the template function, then I will lose precision on my float types.

I’d like to be able to say:

template<class T> bob(T a){
  cout<<if_char_make_int(a)<<endl;
}

But I’m not sure how to do this, or if it is possible.

Any thoughts?

Answer 1

template<class T> void bob(T a){
    std::cout
      << typename boost::mpl::if_<boost::is_same<char, T>, int, T>::type(a)
      << std::endl;
}