Question

I have a call to this php script (only part in question displayed)

if (mysql_num_rows($pquery) == 1) {
   $result = mysql_fetch_assoc($pquery);

   $query_ht = mysql_query("SELECT * FROM coupon WHERE pid='$result[id]'");
   $ht_result = mysql_fetch_array($query_ht); // THIS WILL ALWAYS RETURN 3 ROWS

   //echo json_encode($result); //THis will always contain one row
   //echo json_encode($ht_result); // THIS WILL ALWAYS contain 3 ROWS

UPDATE:

   //echo json_encode(array(
       //'comp' => $result,
       //'ht' => $ht_result)
       // );

This works, but I dont think it is pretty….. Any suggestions

  $query_htl = mysql_query("SELECT * FROM coupon WHERE pid='$result[id]' AND type='L'");
   $query_htg = mysql_query("SELECT * FROM coupon WHERE pid='$result[id]' AND type='G'");
   $query_htr = mysql_query("SELECT * FROM coupon WHERE pid='$result[id]' AND type='R'");
   $ht_resultl = mysql_fetch_assoc($query_htl);
   $ht_resultg = mysql_fetch_assoc($query_htg);
   $ht_resultr = mysql_fetch_assoc($query_htr);
   echo json_encode(array(
       'comp' => $result,
       'htL' => $ht_resultl,
       'htG' => $ht_resultg,
       'htR' => $ht_resultr)
        );

}

When I am echoing one or the other I am ok.. But i do not know how to return everything to jquery

jquery script:

$('#c_search').submit(function(){
       data = ($(this).serialize());

  $.ajax({
      url: 'actions/get_company.php',
      type: 'POST',
      data: data,
      cache: false,
      dataType: 'json',
      success: function(selected){

i can call with:

alert(selected.htL.id);

Answer 1

Just combine all results in common array:

header('Content-type: application/json');
die(json_encode(array(
    'result'    => $result,
    'ht_result' => $ht_result
)));