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Home/ Questions/Q 8038243
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T03:10:18+00:00 2026-06-05T03:10:18+00:00

I have a complex object that I want to be able to pass into

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I have a complex object that I want to be able to pass into a std::ostringstream with the << operator just like a string or int. I want to give the ostringstream the object’s unique id (int) and/or name (string). Is there an operator or method I can implement in my class to allow this to work?

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  1. Editorial Team
    Editorial Team
    2026-06-05T03:10:19+00:00Added an answer on June 5, 2026 at 3:10 am

    Define an operator overload in the same namespace as your class:

    template<typename charT, typename traits>
    std::basic_ostream<charT, traits> &
    operator<< (std::basic_ostream<charT, traits> &lhs, Your_class const &rhs) {
        return lhs << rhs.id() << ' ' << rhs.name();
    }
    

    If the output function needs access to private members of your class then you can define it as a friend function:

    class Your_class {
        int id;
        string name;
    
        template<typename charT, typename traits>
        friend std::basic_ostream<charT, traits> &
        operator<< (std::basic_ostream<charT, traits> &lhs, Your_class const &rhs) {
            return lhs << rhs.id << ' ' << rhs.name;
        }
    };
    

    Note that this does not result in a member function, it’s just a convenient way to declare and define a friend function at once.

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