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Home/ Questions/Q 9059433
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T14:58:37+00:00 2026-06-16T14:58:37+00:00

I have a date column in a table and I want to get week

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I have a date column in a table and I want to get week number for that particular date based on the month from that date irrespective of the day

For example:

01-dec-2012 to 07-dec-2012 should give week number as 1
08-dec-2012 to 14-dec-2012 should give week number as 2
15-dec-2012 to 21-dec-2012 should give week number as 3
22-dec-2012 to 28-dec-2012 should give week number as 4
29-dec-2012 to 31-dec-2012 should give week number as 5

This week number is not dependent on the starting day of the week i.e, it can be any day

How can I write a select statement to get this output in SQL Server 2008?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T14:58:39+00:00Added an answer on June 16, 2026 at 2:58 pm

    You can use DAY (Transact-SQL)

    select ((day(DateColumn)-1) / 7) + 1
    from YourTable
    

    SQL Fiddle

    MS SQL Server 2012 Schema Setup:

    create table YourTable
    (
      D datetime
    )
    
    insert into YourTable 
    select getdate()+Number
    from master..spt_values
    where type = 'P' and
          Number between 1 and 15
    

    Query 1:

    select D,
           ((day(D)-1) / 7) + 1 as W
    from YourTable
    

    Results:

    |                              D | W |
    --------------------------------------
    | January, 03 2013 07:48:54+0000 | 1 |
    | January, 04 2013 07:48:54+0000 | 1 |
    | January, 05 2013 07:48:54+0000 | 1 |
    | January, 06 2013 07:48:54+0000 | 1 |
    | January, 07 2013 07:48:54+0000 | 1 |
    | January, 08 2013 07:48:54+0000 | 2 |
    | January, 09 2013 07:48:54+0000 | 2 |
    | January, 10 2013 07:48:54+0000 | 2 |
    | January, 11 2013 07:48:54+0000 | 2 |
    | January, 12 2013 07:48:54+0000 | 2 |
    | January, 13 2013 07:48:54+0000 | 2 |
    | January, 14 2013 07:48:54+0000 | 2 |
    | January, 15 2013 07:48:54+0000 | 3 |
    | January, 16 2013 07:48:54+0000 | 3 |
    | January, 17 2013 07:48:54+0000 | 3 |
    
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