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Home/ Questions/Q 7516225
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T01:03:56+00:00 2026-05-30T01:03:56+00:00

I have a file that require()’s a namespace, as such: <?php require_once(‘Beer.php’); // This

  • 0

I have a file that require()’s a namespace, as such:

<?php
require_once('Beer.php');   // This file contains the Beer namespace

$foo = new Beer\Carlsburg();
?>

I would like to put the Beer namespace directly in the same file, like this (unworking) example:

<?php
namespace Beer {
    class Carlsburg {}
}

$foo = new Beer\Carlsburg();
?>

However, the PHP interpreter complains that No code may exist outside of namespace. I can therefore wrap $foo declaration in a namespace, but then I must also wrap Beer in that namespace to access it! Here is a working example of what I am trying to avoid:

<?php
namespace Main\Beer {
    class Carlsburg {}
}

namespace Main {
    $foo = new Beer\Carlsburg();
}
?>

Is there any way to include the code for the Beer namespace in the file, yet not wrap the $foo declaration in its own namespace (leave it in the global namespace)?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-30T01:03:57+00:00Added an answer on May 30, 2026 at 1:03 am

    You should use the global namespace :

    <?php
    namespace Beer {
        class Carlsburg {}
    }
    
    
    namespace { // global code
        $foo = new Beer\Carlsburg();
    }
    ?>
    

    See here -> http://php.net/manual/en/language.namespaces.definitionmultiple.php

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