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Home/ Questions/Q 4610806
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T01:10:59+00:00 2026-05-22T01:10:59+00:00

I have a filename in my code as : String NAME_OF_FILE=//sdcard//imageq.png; FileInputStream fis =this.openFileInput(NAME_OF_FILE);

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I have a filename in my code as :

String NAME_OF_FILE="//sdcard//imageq.png";
FileInputStream fis =this.openFileInput(NAME_OF_FILE); // 2nd line

I get an error on 2nd line :

05-11 16:49:06.355: ERROR/AndroidRuntime(4570): Caused by: java.lang.IllegalArgumentException: File //sdcard//imageq.png contains a path separator

I tried this format also:

String NAME_OF_FILE="/sdcard/imageq.png";
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T01:11:00+00:00Added an answer on May 22, 2026 at 1:11 am

    This method opens a file in the private data area of the application. You cannot open any files in subdirectories in this area or from entirely other areas using this method. So use the constructor of the FileInputStream directly to pass the path with a directory in it.

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