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Home/ Questions/Q 6918543
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T09:52:21+00:00 2026-05-27T09:52:21+00:00

I have a fileUploader widget that I’m using to select an xml file. I

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I have a fileUploader widget that I’m using to select an xml file. I then have a button that calls my handler in the viewImpl class when the user submits the selected file. If I understand things correctly, from there I do a submit from the formPanel and the file is on the server.

@UiHandler("calculateComplexityButton")
    void onClickCalculateComplexity(ClickEvent e){
        formPanel.submit();
        //How do I get the inputStream back to here????
        presenter.getTask(inputStream);
    }

My problem is how do I get the inputStream off the server? I tried using an RPC call for all this, but when I try to get the inputStream I’m not pulling anything off the server. I tried:

inputStream = request.getInputStream();

but it appears to be empty. Any ideas on this?

I dropped the RPC code and used a simple HTTPRequest I found here. That gets me to the servlet, but the request doesn’t have the file stream. When I reach this line in the code:

FileItemIterator iter = upload.getItemIterator(request); //Nothing is here in iter.
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  1. Editorial Team
    Editorial Team
    2026-05-27T09:52:22+00:00Added an answer on May 27, 2026 at 9:52 am

    You can not make an upload via RPC, thats why you have to submit your form to a servlet.

    final FormPanel form = new FormPanel();
    form.setEncoding(FormPanel.ENCODING_MULTIPART);
    form.setMethod(FormPanel.METHOD_POST);
    form.setAction("/upload");
    

    So, when you do form.submit() it will send your file to the Action(Servlet). In the server side you can use the lib form apache (commons-fileupload). You have many different way to get your file, you can save on disk, read on memory….

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