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Editorial Team
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Asked: 2026-05-11T22:18:06+00:00

I have a form that can open a sub form (with ShowDialog ). I

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I have a form that can open a sub form (with ShowDialog). I want to make sure that the sub form is being disposed properly when the main form is done.
I tried adding the subform to the components member of the main form, but at the moment I got a ArgumentNullException.
I know I can just instantiate the components myself, but isn’t that a bit dangerous? One day I’ll add a component in the designer view, and that will generate the new Container() line in the designer.cs file, and I’ll never know I have two component instanses running around the heap.
Is there an easier way to make sure the sub form is being disposed?

EDIT – moved my solution to an answer

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1 Answer

  1. Editorial Team

    My current workaround:
    I’ve added the Components property to the form, and am using it to access the collection 

    private IContainer Components{    get { return components ?? (components = new Container());}}
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