Question

i have a form with checkboxes like this:

    <input type="checkbox" name="type[]" value="1" />Fast Food<br>
    <input type="checkbox" name="type[]" value="2" />Table Service<br>
    <input type="checkbox" name="type[]" value="3" />Cafeteria<br>

when i use the brackets in the name (type[]), my php works:

    $type=$_POST['type'];

    echo "types are:";
for ( $counter = 0; $counter < sizeof($type); $counter += 1) {
    echo "<br>".$type[$counter];
}

but my javascript doesn’t work:

    var f = document.addform;
    for (var i=0;i<f.type.length;i++){
        if(f.type[i].checked==true){
            break;
        }
        if(i==(f.type.length-1)){
            alert("No categories entered!");
            valid=false;
        }
    }

however, if i take away the brackets:

<input type="checkbox" name="type" value="1" />Fast Food<br>

then the PHP doesn’t work but the javascript does.

what’s going on here? what should i use?

thanks.

Answer 1

PHP has an unusual system for handling multiple form controls with the same name, it expects the names to include [] but it doesn’t use them in the variable name.

JavaScript doesn’t have that issue. The property will still have the brackets.

Of course, square brackets have special meaning in JS, so you can’t use dot notation to access the property.

f['type[]'][i].checked