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Home/ Questions/Q 9142841
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Editorial Team
  • 0
Editorial Team
Asked: June 17, 20262026-06-17T09:52:38+00:00 2026-06-17T09:52:38+00:00

I have a function that looks like this. It works. Problem This function myFunction

  • 0

I have a function that looks like this. It works.

Problem

This function myFunction is called by many other functions and depending on which one it should do something different on success.

Question

How is this solved? Some kind of callback? or do I have to send an extra parameter for the function to know?

Code

function myfunction()
{
    var value = "myvalue";
    var post_url = "ajax.php";

    $.post(  
        post_url,
        {
             value: value,
        },
            function(responseText){  
                var json = JSON.parse(responseText);
                if(json.success)
                {
                    console.log('success'); 
                }
            }
        );
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T09:52:39+00:00Added an answer on June 17, 2026 at 9:52 am

    Add a function parameter and call it on success:

    function myfunction(callback)
    {
        var value = "myvalue";
        var post_url = "ajax.php";
    
        $.post(  
            post_url,
            {
                 value: value,
            },
                function(responseText){  
                    var json = JSON.parse(responseText);
                    if(json.success)
                    {
                        console.log('success'); 
                        //call callback 
                        callback();
    
                    }
                }
            );
        }
    }
    
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