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Home/ Questions/Q 8521991
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T06:58:55+00:00 2026-06-11T06:58:55+00:00

I have a function(orders) with many php includes in a file called extract.php http://example.com/application/dir1/dir2/dir3/extract.php

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I have a function(orders) with many php includes in a file called extract.php

http://example.com/application/dir1/dir2/dir3/extract.php

function orders ($username)
{
 require ("functions.inc.php");
 define("DATAGRID_DIR", "./../datagrid/");
 define("PEAR_DIR", "./../datagrid/pear/");
 require_once (DATAGRID_DIR . 'datagrid.class.php');
 require_once (PEAR_DIR . 'PEAR.php');
 require_once (PEAR_DIR . 'DB.php');
 require_once ('./../datagrid/classes/database.class.php');

//function code here
}

I have another file(install.php) that calls this function inside the same directory and it works very well.

<?php
include ("extract.php");
orders ("643443876996");
?>

However, when i include it in another function in this path
http://example.com/orders/getorder.php, it gives me error that it cannot find my files ‘datagrid.class.php’;

    <?php
    include ("include('../application/dir1/dir2/dir3/extract.php');");
    orders ("643443876996");
    ?>

How can I get the path referencing correct?

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  1. Editorial Team
    Editorial Team
    2026-06-11T06:58:57+00:00Added an answer on June 11, 2026 at 6:58 am

    Reference from the server root, either with $_SERVER[‘DOCUMENT_ROOT’] or

    require_once (DATAGRID_DIR . ‘/application/dir1/dir2/dir3/datagrid.class.php’);

    etc…

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