Question

I have a list of words, with patterns either “term” or “termNUM”, e.g. “term” or “term02”.
I want to save all terms that ends with digit but remove the ones are purely alphabets.

I am totally new to regex, I tried few options, and get the following:

new_list = [x for x in old_list if re.match("[(^a-zA-Z_)\d]", x)]

It is not working, I know it only need a small tweak somewhere, but with my limited skill in regex, cannot do it quickly.

Tips are highly appreciated.

Answer 1

r".*\d"

That’s any character (.), any number of times (*) followed by a digit (\d). Your list comprehension is correct.

You could also do

[x for x in old_list if x[-1].isdigit()]

assuming the empty string is not in the list. I’d prefer this option, as it’s more explicit as to what it does.