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Home/ Questions/Q 9216423
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T02:24:52+00:00 2026-06-18T02:24:52+00:00

I have a list that is kind of like this: <li class=listElement semiUniqueCLassOne unique-class=semiUniqueCLassOne

  • 0

I have a list that is kind of like this:

<li class="listElement semiUniqueCLassOne" unique-class="semiUniqueCLassOne" style="display:none;">one</li>
<li class="listElement semiUniqueCLassOne" unique-class="semiUniqueCLassOne" style="display:none;">two</li>
<li class="listElement semiUniqueCLassOne" unique-class="semiUniqueCLassOne" style="display:none;">three</li>
<li class="listElement semiUniqueCLassTwo" unique-class="semiUniqueCLassTwo" style="display:none;">four</li>
<li class="listElement semiUniqueCLassTwo" unique-class="semiUniqueCLassTwo" style="display:none;">five</li>
<li class="listElement semiUniqueCLassThree" unique-class="semiUniqueCLassThree" style="display:none;">six</li>

I’m trying to only show the first of each of the semiUniqueCLass so I’m attempting to do it like this:

$('.listElement').each(function(){
    var uniqueClass = $(this).attr('unique-class');
    if($('.'+uniqueClass).is(':first')){
        $(this).show();
    }
});

this doesn’t work… what ways can I make it work? tried several, a bit stuck.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T02:24:53+00:00Added an answer on June 18, 2026 at 2:24 am

    Just use the .first() method.

    $('.listElement').each(function(){
        var uniqueClass = $(this).attr('unique-class');
        $('.'+uniqueClass).first().show();
    });
    

    And the working demo.

    Another solution is shown as below:

    var clazzs = $('.listElement').map(function() {
      return $(this).attr('unique-class');
    });
    
    $.unique(clazzs).each(function() {
      $('.'+this).first().show();
    });
    

    Also the working demo.

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