Question

I have a makefile that builds, runs unit tests, memory leaks etc. But is there a way I can stop malloc(), free(), calloc() and the like from being used in the source code?

I have replacement memory functions that handle things like mocking. Is there a way I can enforce EagleMemory_Free() to be used instead of free(), for example.

My replacement functions have a different signature so I can’t simply create a macro that points the internal one to my own:

void* EagleMemory_Allocate(char *id, size_t size);
void EagleMemory_Free(void *ptr);
void** EagleMemory_MultiAllocate(char *id, size_t size, int quantity);
void EagleMemory_MultiFree(void **ptr, int quantity);
void EagleMemory_MockInit(void);
void EagleMemory_Mock(char *id);
void EagleMemory_MockFinish(void);
int EagleMemory_GetMockInvocations(void);

Oh, I should also point out I don’t want to replace the function at runtime and cause my software to crash – that’s just stupid. I want to catch the use of the std function at build time or through some other script before the software runs.

Answer 1

Thanks to Alexey Frunze. The nm command was exactly what I needed. I added this to my makefile:

NM = nm $(OBJS)/*.o -o 2>&1 | grep -v EagleMemory.o | grep -w '_malloc\|_calloc\|_free'

leaks: build_eagle_test
    if [ `$(NM) | wc -l` -gt 0 ]; then \
        echo "\n==> Do not use stdlib memory functions, use EagleMemory functions instead. <=="; \
        $(NM); \
        exit 1; \
    fi

    ...

Works great!