Question

I have a method with the following definition:

void foo(int i = 0, bool flag = false) {}

I want to call foo() by passing only the second argument:

foo(true);

But like this it will always pass it to the first parameter (i).
Is there any other solution I can pass my argument to the second parameter ? Or the only way is to pass the first one also.

foo(0, true);

Answer 1

Technically no. But you can fake it with overloads, thusly:

void foo(bool flag)
{
    foo(0,flag);
}