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Home/ Questions/Q 8622347
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T07:01:59+00:00 2026-06-12T07:01:59+00:00

I have a piece of code below where it contains buttons and each button

  • 0

I have a piece of code below where it contains buttons and each button contains its own hidden input:

<?php
$a = range("A","Z");
?>

<table id="answerSection">
<tr>

<?php
$i = 1;
foreach($a as $key => $val){
    if($i%7 == 1) echo"<tr><td>";
    echo"<input type=\"button\" onclick=\"btnclick(this);\" value=\"$val\" id=\"answer".$val."\" name=\"answer".$val."Name\" class=\"answerBtns answers answerBtnsOff\">";
    echo"<input type=\"hidden\" value=\"1\" id=\"hiddenAnswer".$val."\" name=\"hidden".$val."\" class=\"onButtons\">";
    if($i%7 == 0) echo"</td></tr>";
    $i++;
}
?>
</tr>

But what I want to do is copy this control using jquery when the control is appended into a table row. I have done 90% of it but my question is what is the best way to be able to add the hidden inputs for each button in the code below:

function insertQuestion(form) {   

            var context = $('#answerSection');
    var currenttotal = context.find('.answerBtnsOn').length;        



    var $tbody = $('#qandatbl > tbody'); 
    var $tr = $("<tr class='optionAndAnswer' align='center'>");
    var $td = $("<td class='extratd'>");
    var $answer = $("<div class='answer'>3. Answer:<br/></div>");


var $this, i=0, $row, $cell;
$('#optionAndAnswer .answers').each(function() {
    $this = $(this);
    if(i%7 == 0) {
        $row = $("<tr/>").appendTo($answer);
        $cell = $("<td/>").appendTo($row);
    }
    var $newBtn = $("<input class='answerBtnsRow answers' type='button' style='display:%s;' onclick='btnclick(this);' />".replace('%s',$this.is(':visible')?'inline-block':'none')).attr('name', $this.attr('name')).attr('value', $this.val()).attr('class', $this.attr('class')).attr('id', $this.attr('id')+'Row');

    $newBtn.appendTo($cell);

    i++;
});


    $tr.append($td);
    $td.append($answer);
    $tbody.append($tr); 


}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T07:02:00+00:00Added an answer on June 12, 2026 at 7:02 am

    Try this

    var elem = $(this)
    var $newBtn =
            $(document.createElement('input'), {
                type : 'button',
                onclick : 'btnclick(this);',
                name : elem.attr('name'),
                value : elem.val(),
                class : elem.attr('class'),
                id : elem.attr('id') + 'Row'
              },
              css : {
                   display : elem.is('visible') ? 'inline-block' : 'none'
              }
            );
    $newBtn.appendTo($cell);
    
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