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Home/ Questions/Q 6810081
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T20:09:46+00:00 2026-05-26T20:09:46+00:00

I have a piece of code in ALLOY I am trying to do a

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I have a piece of code in ALLOY I am trying to do a restaurant reservation system and I have this sig and relation between them.

abstract sig Table{
breakfast: one breakFast,
lunch: one Lunch,
dinner: one Dinner
}

sig Free{

}

sig Reserved{

}

sig breakFast {
breakfastfree:one Free,
breakfastReserved:one Reserved
}

sig Lunch {
Lunchfree:one Free,
LunchReserved:one Reserved

} 

sig Dinner  {
Dinnerfree:one Free,
 DinnertReserved:one Reserved
}


fact{
all t1,t2 : Table | t1 != t2 => t1.breakfast != t2.breakfast
all t1,t2 : Table | t1 != t2 => t1.lunch != t2.lunch
all t1,t2 : Table | t1 != t2 => t1.dinner != t2.dinner

 }

 pred RealismConstraints []{

 #Table = 4

 }
  run RealismConstraints for 20

I want to put a fact that for breakfast it can be reserved or free NOT BOTH and in lunch and dinner the same thing any ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-26T20:09:47+00:00Added an answer on May 26, 2026 at 8:09 pm

    First, the way you’ve constrained breakfastfree and breakfastReserved it will always be both. You need to use lone (no object or one):

    sig breakFast {
      breakfastfree:lone Free,
      breakfastReserved:lone Reserved
    }
    

    Then, you could write the fact:

    fact{
      all t: Table | let breakf = t.breakfast |
        #(breakf.breakfastfree+breakf.breakfastReserved) = 1
    }
    

    or, simpler, just:

    sig breakFast {
      breakfastfree: lone Free,
      breakfastReserved: lone Reserved
    }
    {
      #(breakfastfree+breakfastReserved) = 1
    }
    

    However, I’d suggest that you just go with something like

    sig breakFast {
        breakfastReserved: lone Reserved
    }
    

    and treat no breakfastReserved as “free”. You don’t need any further facts then.

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