Question

I have a program in C, which takes 2 arguments, filename and text. I want to write a script in bash, which also take 2 arguments, path and file extension, will iterate through all files in given path and give to my program in C as argument files with the givenextension only and text.

Heres my program in C, nothing special really:

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char **argv)
{
    if(argc < 3)
    {
        fprintf(stderr, "Give 2 args!\n");
        exit(-1);
    }

    char *arg1 = argv[1];
    char *arg2 = argv[2];

    fprintf(stdout, "You gave: %s, %s\n", arg1, arg2);

    return 0;
}

and my bash script:

#!/bin/bash

path=$1
ext=$2
text=$3

for file in $path/*.$ext
do
    ./app | 
    {
        echo $file 
        echo $text
    }
done

I use it like this: ./script /tmp txt hello and it should give as arguments all txt files from /tmp and ‘hello’ as text to my C program. No it only shows Give 2 args! 🙁 Please, help.

Answer 1

Right now you’re not actually passing any arguments to the program in your script.

Just pass the arguments normally:

./app "$file" "$text"

I put the arguments in double-quotes to make the shell see the variables as single arguments, in case they contain spaces.