I have a program which takes various command line arguments. For the sake of simplification, we will say it takes 3 flags, -a, -b, and -c, and use the following code to parse my arguments:
int c;
while((c = getopt(argc, argv, ":a:b:c")) != EOF)
{
switch (c)
{
case 'a':
cout << optarg << endl;
break;
case 'b':
cout << optarg << endl;
break;
case ':':
cerr << "Missing option." << endl;
exit(1);
break;
}
}
note: a, and b take parameters after the flag.
But I run into an issue if I invoke my program say with
./myprog -a -b parameterForB
where I forgot parameterForA, the parameterForA (represented by optarg) is returned as -b and parameterForB is considered an option with no parameter and optind is set to the index of parameterForB in argv.
The desired behavior in this situation would be that ':' is returned after no argument is found for -a, and Missing option. is printed to standard error. However, that only occurs in the event that -a is the last parameter passed into the program.
I guess the question is: is there a way to make getopt() assume that no options will begin with -?
See the POSIX standard definition for
getopt. It says thatAs for that detection,
It looks like
getoptis defined not to do what you want, so you have to implement the check yourself. Fortunately, you can do that by inspecting*optargand changingoptindyourself.