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Home/ Questions/Q 298407
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T06:43:44+00:00 2026-05-12T06:43:44+00:00

I have a simple custom exception defined like like the following but I don’t

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I have a simple custom exception defined like like the following but I don’t like having to use the Throw function and I really don’t like having both Throw and a Throw2 functions. Is there a more elegant way of doing this? Is there a way of throwing MyError or Error directly without the intermediate function?

#light

module Utilities.MyException

type MyError(code : int, msg : string) =
    member e.Msg  = msg
    member e.Code = code
    new (msg : string) = MyError(0, msg)

exception Error of MyError

let public Throw (msg : string) =
    let err = new MyError(msg)
    raise (Error err)

let public Throw2 (code : int) (msg : string) =
    let err = new MyError(code, msg)
    raise (Error err)

I’m using it like the following but I’d like to use one of the variants that didn’t work

Throw(System.String.Format("Could not parse boolean value '{0}'", key))

//The string isn't of the correct type for Error
//raise(Error(System.String.Format("Could not parse boolean value '{0}'", key)))

//MyError isn't compatible with System.Exception
//raise(MyError(System.String.Format("Could not parse boolean value '{0}'", key)))
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  1. Editorial Team
    Editorial Team
    2026-05-12T06:43:44+00:00Added an answer on May 12, 2026 at 6:43 am

    Just ignore exception construct and define the exception class – that is, one deriving from System.Exception – directly, as in C#:

    type MyError(code : int, msg : string) =
        inherit Exception(msg)
        member e.Code = code
        new (msg : string) = MyError(0, msg)
    
    raise(MyError("Foo"))
    raise(MyError("Foo", 1))
    

    Note that I removed Msg member, because Exception has an equivalent Message property already.

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