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Home/ Questions/Q 6980967
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:05:41+00:00 2026-05-27T18:05:41+00:00

I have a simple XML file <servers> <server> <id>Server0</id> </server> <server> <id>Server1</id> </server> <server>

  • 0

I have a simple XML file

<servers>  
<server>  
<id>Server0</id>  
</server>  
<server>  
<id>Server1</id>  
</server>  
<server>  
<id>Server2</id>  
</server>  
<server>  
<id>Server3</id>  
</server>  
<servers> 

I have two JAXB classes. One for Servers and one for Server. The Servers one is simply a wrapper and does nothing else. Anyway I could ditch it? I would need to make the Server class smart enough. Currently it is:

@XmlAccessorType(XmlAccessType.FIELD)  
@XmlRootElement(name = "server")  
public class JAXBServer {  
    protected String id;  

    public String getId() {  
        return id;  
    }  

    public void setId(String id) {  
        this.id = id;  
    }  
}   

And requires the Servers class.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:05:42+00:00Added an answer on May 27, 2026 at 6:05 pm

    Using the standard JAXB APIs your Servers class is required. If you are implementing something like a JAX-RS service however you can use a List<Server> and a wrapper element will automatically be added for you.

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