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Home/ Questions/Q 8896989
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T00:13:04+00:00 2026-06-15T00:13:04+00:00

I have a single regex and I want to replace each match in the

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I have a single regex and I want to replace each match in the array of matches with a corresponding array of replacements in the most efficient way possible.

So for instance, I have:

$string = '~~hello~~ there, how ~~are~~ ~~you~~?';

$pattern = '/~~(.*?)~~/';

$replacements = array();
$replacements[0] = 'hi';
$replacements[1] = 'am';
$replacements[2] = 'i';

and I want to turn $string into:

hi there, how am i?

Initially I hoped it’d be as simple as:

$string = preg_replace($pattern, $replacements, $string);

but it doesn’t seem to work. So the first question is: if $replacements is an array, then does $string must also be an array?

Now, I can come up with (seemingly) inefficient ways to do this, like counting the number of matches and making an array filled with the appropriate number of identical regexes. But this leads us into question two: is there a more efficient way? How would you do it, PHP pros?

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  1. Editorial Team
    Editorial Team
    2026-06-15T00:13:05+00:00Added an answer on June 15, 2026 at 12:13 am

    You can use a simple eval trick here:

    print preg_replace('/~~(\w+)~~/e', 'array_shift($replacements)', $st);
    

    array_shift will simply fetch the first entry from your replacement array.

    Better would be using a map though ("hello" => "hi").

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