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Home/ Questions/Q 8643213
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T11:58:37+00:00 2026-06-12T11:58:37+00:00

I have a sitution where I need to pass a string in order to

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I have a sitution where I need to pass a string in order to do an IN

    declare @searchString varchar(50)
    set @searchString = ' ''Nestle'',''UFI'' '

    select * from tbl1 where CompanyName IN (@SearchString) 

does’t work.

But if I do:

    select * from tbl1 where CompanyName IN ('Nestle','UFI')

It works fine. I cannot understand why one work and the other doesn’t

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T11:58:38+00:00Added an answer on June 12, 2026 at 11:58 am

    When you use IN it looks at a set and not a single string expression. Because of this
    you need to implement a function such as CsvToInt to return a table, like so:

    CREATE Function [dbo].[CsvToInt] ( @Array varchar(1000)) 
    returns @IntTable table 
        (IntValue int)
    --Parse comma seperated value parameters
    --To be used in SELECT blah WHERE blah IN (...)
    --This function returns int, but may be modified to return any datatype
    AS
    begin
    
        declare @separator char(1)
        set @separator = ','
    
        declare @separator_position int 
        declare @array_value varchar(1000) 
    
        set @array = @array + ','
    
        while patindex('%,%' , @array) <> 0 
        begin
    
          select @separator_position =  patindex('%,%' , @array)
          select @array_value = left(@array, @separator_position - 1)
    
            Insert @IntTable
            Values (Cast(@array_value as int))
    
          select @array = stuff(@array, 1, @separator_position, '')
        end
    
        return
    end
    

    And then you can use this function from say within a stored procedure like so:

    SELECT Blah
    FROM MyTable
    WHERE Foo IN (SELECT * FROM dbo.CsvToInt(@Parameter))
    

    Where @Parameter contains a comma seperated string of values like:

    Nestle, UFI, Test

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