Question

I have a small math problem I am trying to solve

Given a number x and resolution y, I need to find the next x’ with the required resolution.

e.g.

x = 1.002     y = 0.1   x'= 1.1  x = 0.348     y = 0.1   x'= 0.4  x = 0.50      y = 1     x'= 1  x = 0.32      y = 0.05     x'= 0.35 

Is there any smart way of doing this in Python?

Answer 1

import math  def next_multiple(x, y):     return math.ceil(x/y)*y  def try_it(x, y):     print x, y, next_multiple(x, y)  for x, y in [     (1.002, 0.1),     (0.348, 0.1),     (0.50, 1),     (0.32, 0.05)     ]:     try_it(x, y) 

produces:

1.002 0.1 1.1 0.348 0.1 0.4 0.5 1 1.0 0.32 0.05 0.35 

I think your first example output is wrong, The correct answer for x’ is 1.1, right?