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Home/ Questions/Q 7158769
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T13:07:16+00:00 2026-05-28T13:07:16+00:00

I have a struct like so, typedef struct Player { char *name; char *heroID;

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I have a struct like so,

typedef struct Player {
    char *name;
    char *heroID;
    char *heroName;
    int slotNo;
} Player;

I then define it as a statically allocated array

Player players[10];

My program may have to exit when I haven’t completely allocated all the char* fields of each Player struct in players and I have decided that I will free any allocated memory before exiting even though modern OS’s don’t require you to because it is good programming practice to do so.

However, I can’t just loop through players and free(player[i].name) etc because it could be uninitialized.

Is the only way of getting around this problem, manually initializing each char pointer to NULL after I define the array and then when freeing memory, check to see if the pointer is NULL or not to decide whether I should free it?

If so, what is the best way of initializing, for loop and manual assignment or defining values when i declare the players array through the use of braces. Or is there another way?

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  1. Editorial Team
    Editorial Team
    2026-05-28T13:07:17+00:00Added an answer on May 28, 2026 at 1:07 pm

    Is the only way of getting around this problem, manually initializing each char pointer to NULL after I define the array and then when freeing memory, check to see if the pointer is NULL or not to decide whether I should free it?

    It’s definitely not the only way, but it’s the most common and standard way to do so. In fact, most programmers will always initialize pointers to zero to prevent seg faults.

    The best way to initialize is to just create a for loop or memset everything to zero (or use calloc, which is the easiest).

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