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Home/ Questions/Q 8686207
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T22:47:16+00:00 2026-06-12T22:47:16+00:00

I have a table (t1) as follows: t1 <- array(1:20, dim=c(10,10)) [,1] [,2] [,3]

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I have a table (t1) as follows:

t1 <- array(1:20, dim=c(10,10))

      [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
 [1,]    1   11    1   11    1   11    1   11    1    11
 [2,]    2   12    2   12    2   12    2   12    2    12
 [3,]    3   13    3   13    3   13    3   13    3    13
 [4,]    4   14    4   14    4   14    4   14    4    14
 [5,]    5   15    5   15    5   15    5   15    5    15
 [6,]    6   16    6   16    6   16    6   16    6    16
 [7,]    7   17    7   17    7   17    7   17    7    17
 [8,]    8   18    8   18    8   18    8   18    8    18
 [9,]    9   19    9   19    9   19    9   19    9    19
[10,]   10   20   10   20   10   20   10   20   10    20

I want to transform this table to either 1 or 0. If the cells number is >5, we give it a 1, if the cells number is <5 or = 5, we give it a 0. Thus after transformation, table t1 will become the followings:

      [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
 [1,]    0   1    0   1    0    1    0    1    0    1
 [2,]    0   1    0   1    0    1    0    1    0    1
 [3,]    0   1    0   1    0    1    0    1    0    1
 [4,]    0   1    0   1    0    1    0    1    0    1
 [5,]    0   1    0   1    0    1    0    1    0    1
 [6,]    1   1    1   1    1    1    1    1    1    1
 [7,]    1   1    1   1    1    1    1    1    1    1
 [8,]    1   1    1   1    1    1    1    1    1    1
 [9,]    1   1    1   1    1    1    1    1    1    1
[10,]    1   1    1   1    1    1    1    1    1    1

Which commands should I used?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T22:47:17+00:00Added an answer on June 12, 2026 at 10:47 pm

    You can just use an ifelse() statement:

    ifelse(t1 > 5, 1, 0)
    

    Since a statement like t1 > 5 will result in a matrix of TRUE and FALSE, and since R treats TRUE as “1” and FALSE as “0“, for this particular transformation, you could also do:

    (t1 > 5)+0
          [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
     [1,]    0    1    0    1    0    1    0    1    0     1
     [2,]    0    1    0    1    0    1    0    1    0     1
     [3,]    0    1    0    1    0    1    0    1    0     1
     [4,]    0    1    0    1    0    1    0    1    0     1
     [5,]    0    1    0    1    0    1    0    1    0     1
     [6,]    1    1    1    1    1    1    1    1    1     1
     [7,]    1    1    1    1    1    1    1    1    1     1
     [8,]    1    1    1    1    1    1    1    1    1     1
     [9,]    1    1    1    1    1    1    1    1    1     1
    [10,]    1    1    1    1    1    1    1    1    1     1
    
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