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Home/ Questions/Q 7952421
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T02:51:25+00:00 2026-06-04T02:51:25+00:00

I have a typedef in an if macro, something like: #ifdef BLA_BLA typedef int

  • 0

I have a typedef in an if macro, something like:

#ifdef BLA_BLA
typedef int typeA
#elseif 
typedef double tyeA
#endif
printf("%d" , a); printf("%l" , a);

I am wondering what is the best approach when I write a printf for this case? (%d or %l).

I know I can define a fixed string in the macro as well. But is it the best way?

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  1. Editorial Team
    Editorial Team
    2026-06-04T02:51:26+00:00Added an answer on June 4, 2026 at 2:51 am

    Do you really want to define a type as either integer or floating-point? They’re both numeric, but their behavior is so different in many ways that writing code that works correctly in either case is going to be difficult.

    In many cases, you can convert to a type that’s wide enough to cover the ranges of both possible types. A simple example:

    #include <stdio.h>
    
    #ifdef BLA_BLA
    typedef int num_type;
    #else
    typedef long num_type;
    #endif
    
    int main(void) {
        num_type x = 42;
        printf("x = %ld\n", (long)x);
        return 0;
    }
    

    More generally, you can convert to intmax_t or uintmax_t, defined in <stdint.h> or <inttypes.h>, using "%jd" or "%ju", respectively.

    You can almost do the same thing by converting everything to long double, but that can lose precision for large integer values.

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