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Home/ Questions/Q 7611419
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T01:39:51+00:00 2026-05-31T01:39:51+00:00

I have typedef unsigned int DWORD; void write_str(string str, char** buf) { DWORD len

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I have

typedef unsigned int DWORD;

void write_str(string str, char** buf) {
    DWORD len = str.size();
    **buf = len;
    *buf += sizeof(len);
    memcpy(*buf, str.c_str(), len);
    *buf += len;
}

This code, and only 1 byte is overwriten in **buf = len; if i have i.e. 7 in len while 4 should be, since sizeof(DWORD) = 4

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  1. Editorial Team
    Editorial Team
    2026-05-31T01:39:52+00:00Added an answer on May 31, 2026 at 1:39 am

    As buf is a char **, **buf is a char. It can hold only a single byte. Therefore, only a single byte is written to it.

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