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Home/ Questions/Q 6553675
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T12:36:37+00:00 2026-05-25T12:36:37+00:00

I have defied a variable type as follows: typedef unsigned int color[3]; I then

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I have defied a variable type as follows:

typedef unsigned int color[3];

I then created a vector of that type:

vector<color> RGB;

Now, say I want to push back a new element to this vector. What is the right syntax? My g++ won’t let me do something like:

color temp = {255, 255, 255};
RGB.push_back(temp);

Which I thought would be a good syntax 🙁 Any suggestions are very much appreciated

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T12:36:38+00:00Added an answer on May 25, 2026 at 12:36 pm

    You can’t use raw arrays as types for any of the standard containers.

    The types must be assignable (they have either an implicit or explicit operator =) and constructable (they have either implicit or explicit default and copy constructors).

    You could wrap your array type in a struct to allow use with the standard containers:

    struct my_colour_array
    {
        unsigned int colours[3];
    };
    

    In this case, the compiler will generate implicit operators and constructors. If you want different behaviour you can define your own.

    For your use it might make sense to have an initialising constructor:

    struct my_colour_array
    {
        unsigned int colours[3];
    
    // initialising constructor
        my_colour_array (unsigned int r, unsigned int g, unsigned int b)
        {
            this->colours[0] = r;
            this->colours[1] = g;
            this->colours[2] = b;
        }
    };
    

    Then you can setup your vector:

    std::vector<my_colour_array> myvector;
    // push data onto container via a temporary
    myvector.push_back(my_colour_array(0,255,0));
    // etc
    

    Hope this helps.

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