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Home/ Questions/Q 8149017
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T14:45:55+00:00 2026-06-06T14:45:55+00:00

I have a ‘users’ SQL table structure like this (the ID is randomly generated,

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I have a ‘users’ SQL table structure like this (the ID is randomly generated, not auto-incremented):

ID    name     deleted    lastActive
3242  Joe      0          20-6-2012 23:14
2234  Dave     0          20-6-2012 23:13
2342  Simon    1          20-6-2012 23:02
9432  Joe      1          20-6-2012 22:58

There can be multiple deleted (deleted=1) users with the same name, but only 1 undeleted user with the same name (so adding Simon is fine, but Dave is not). How can I insert only if there is not a record already with the same name and deleted=0, in one SQL query? I need something like this:

INSERT INTO users (ID, name) VALUES ($id, $name) 
    WHERE NOT EXISTS (SELECT 1 FROM users WHERE name = $name AND deleted = 0)

But this is not correct syntax.

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  1. Editorial Team
    Editorial Team
    2026-06-06T14:45:56+00:00Added an answer on June 6, 2026 at 2:45 pm

    Setup a LEFT JOIN with

    • Subquery A containing your random number aliased as ID and $name aliased as name.
    • Subquery B selects name = $name that is not deleted.
    • LEFT JOIN A to B and return A.* if it does not have a right side counterpart for the LEFT JOIN

    This is the query

    INSERT INTO users (ID,name)
    SELECT A.* FROM
    (SELECT RAND() ID,'$name' name) A LEFT JOIN
    (SELECT name FROM users WHERE name='$name' AND deleted=0) B
    USING (name) WHERE B.name IS NULL;
    
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