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Home/ Questions/Q 8554865
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T14:58:54+00:00 2026-06-11T14:58:54+00:00

I have a worksheet, in where I need a search that does more than

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I have a worksheet, in where I need a search that does more than one query. The problem I am running into is this:

On the workbook there are two tabs, the first is Jobs, the second is OOR. In OOR there are multiple columns empty, Order Qty., Orig Promise Date, and Shop Order.

Now I know there are duplicates, and this is fine, what I am looking at now is to use Column B in OOR is a refrence. So in this case use B3 as the refrence point. which is a partial number of 48900421 Rev 2. What I want to do is this, use two refrence points.

I want to look up B3 in OOR, and use two points of refrence to gurantee the correct job is refrenced. Those two columns to refrence is in Jobs. The first is Column B which will always equal Dakota Systems, Inc., and the other will reference Column C, but this is where I don’t know what to do here, I since C3 in OOR only shows 48900421, it will never find 48900421 Rev 2I thought about using something like this:

=IFERROR(INDEX(Jobs!$E:$E,MATCH(1,INDEX((OOR!$C:$C=$B3)*(Jobs!$C:$C="Dakota Systems, Inc."),1),0)),"")

But for some reason I am getting a blank when I don’t think I should be. I’m loosing my sanity this late in the week, can someone help?

https://dl.dropbox.com/u/3327208/Excel/twosearches.xlsx

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  1. Editorial Team
    Editorial Team
    2026-06-11T14:58:56+00:00Added an answer on June 11, 2026 at 2:58 pm

    You don’t seem to be referencing the right columns….and also you need a zero in the second INDEX function, not a 1

    Try this version in in OOR!I3 copied down, using ISNUMBER(FIND to find your part number within other text:

    =IFERROR(INDEX(Jobs!E$3:E$1000,MATCH(1,INDEX(ISNUMBER(FIND(B3,Jobs!C$3:C$1000))*(Jobs!B$3:B$1000="Dakota Systems, Inc."),0),0)),"")

    format in required date format

    Revised re comment below:

    =IFERROR(INDEX(Jobs!E$3:E$1000,MATCH(1,INDEX(ISNUMBER(FIND(B3,Jobs!C$3:C$1000))*(Jobs!B$3:B$1000="Dakota Systems, Inc.")*(Jobs!A$3:A$1000=M3),0),0)),"")

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