Question

I have a XSL that needs to filter out specific data found in the XML.

Somewhere in my XML there will be a node like:

<id root="2.16.840.1.113883.3.51.1.1.6.1" extension="9494949494949" />

The XSL I have below deletes the extension node and adds a nullFlavor=”MSK” to the node.

What I need to do now, is take the value from the extension node, and search the entire XML document for that value, and replace it with **.

But I’m not sure how to take the extension attribute, and find all instances of that value in the XML (they could be burried in text and inside attributes) and turn them into ** (4 *).

The example below is just an example. I cannot hard code the XSL to look at specific nodes, it needs to look through all text / attribute text in the xml (reason for this is there are 5+ different versions of XML that this will be applied to).

I need to find the Extension in the node, then replace (delete really) that value from the rest of the XML. I’m looking for a 1 solution fits all messages, so a global search->wipe of the Extension value.

Example:

        <identifiedPerson classCode="IDENT">
                <id root="2.16.840.1.113883.3.51.1.1.6.1" extension="9494949494949" displayable="true" />
                <addr use="PHYS">
                    <city>KAMLOOPS</city>
                    <country>CA</country>
                    <postalCode>V1B3C1</postalCode>
                    <state>BC</state>
                    <streetAddressLine>1A</streetAddressLine>
                    <streetAddressLine>2A</streetAddressLine>
                    <streetAddressLine>9494949494949</streetAddressLine>
                    <streetAddressLine>4A</streetAddressLine>                        
                </addr>
                <note text="9494949494949 should be stars"/>

Should be (The below XSLT already masks the extension in the node with the matching OID).

            <identifiedPerson classCode="IDENT">
                <id root="2.16.840.1.113883.3.51.1.1.6.1" nullFlavor="MSK" displayable="true" />
                <addr use="PHYS">
                    <city>KAMLOOPS</city>
                    <country>CA</country>
                    <postalCode>V1B3C1</postalCode>
                    <state>BC</state>
                    <streetAddressLine>1A</streetAddressLine>
                    <streetAddressLine>2A</streetAddressLine>
                    <streetAddressLine>****</streetAddressLine>
                    <streetAddressLine>4A</streetAddressLine>                        
                </addr>
                <note text="**** should be stars"/>

Any help would be appreciated.

I am able to use XSL 2.0

I have the current XSL.IT works fine. It matches any tag where the root is ‘2.16.840.1.113883.3.51.1.1.6.1’, kills all attributes and adds a nullFlavor=”MSK”. However, this will not search the entire XML for that same #.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" indent="yes"/>
    <xsl:param name="attrToKeep" select="'root'" />

    <xsl:template match="* | node()">
      <xsl:copy>
        <xsl:apply-templates select="node()|@*" />
      </xsl:copy>
    </xsl:template>

    <xsl:template match="@*">
      <xsl:choose>
        <xsl:when test="../@root = '2.16.840.1.113883.3.51.1.1.6.1'">
          <xsl:copy-of select=".[contains($attrToKeep, name())]" />     
          <xsl:attribute name="nullFlavor">MSK</xsl:attribute>
          <!-- Need some way to use the value found in this node and hide the extension -->
        </xsl:when>
        <xsl:otherwise>
          <xsl:copy-of select="." />
        </xsl:otherwise>
      </xsl:choose>
    </xsl:template>
</xsl:stylesheet>

Any help would be appreciated.

Thanks,

Answer 1

Try using a variable to hold the value of the text to be replaced. Like this:

<xsl:variable
    name="rootVar"
    select="//*[@root = '2.16.840.1.113883.3.51.1.1.6.1']/@extension" />

And then you should just be able to use the replace function to replace them.

<xsl:template match="'//@*' | text()">
    <xsl:sequence select="replace(., $rootVar, '****')"/>
</xsl:template>